How to Prove tan^2(theta) +1=sec^2(theta)

 


Use the basic identity

sin⁡2(θ)+cos⁡2(θ)=1

\sin^2(\theta) + \cos^2(\theta) = 1

Divide both sides of the identity by cos⁡2(θ)\cos^2(\theta)

sin⁡2(θ)cos⁡2(θ)+cos⁡2(θ)cos⁡2(θ)=1cos⁡2(θ)\frac{\sin^2(\theta)}{\cos^2(\theta)} + \frac{\cos^2(\theta)}{\cos^2(\theta)} = \frac{1}{\cos^2(\theta)} tan⁡2(θ)+1=sec⁡2(θ)\tan^2(\theta) + 1 = \sec^2(\theta)

Final Answer:

tan⁡2(θ)+1=sec⁡2(θ)\boxed{\tan^2(\theta) + 1 = \sec^2(\theta)}

This proves the identity.




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